What is expand (5(2cos(2)x+4cos(2x)+3))/4 ?

The solution to expand (5(2cos(2)x+4cos(2x)+3))/4 is (5cos(2)x)/2+5cos(2x)+15/4

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expand (5(2cos(2)x+4cos(2x)+3))/4

expand

\frac{5 ( 2 cos ( 2 ) x + 4 cos ( 2 x ) + 3 )}{4}

\frac{5 cos ( 2 ) x}{2} + 5 cos (2 x) + \frac{15}{4}

Solution steps

\frac{5 ( 2 cos ( 2 ) x + 4 cos ( 2 x ) + 3 )}{4}

Expand

5 (2 cos (2) x + 4 cos (2 x) + 3) : 10 cos (2) x + 20 cos (2 x) + 15

= \frac{10 cos ( 2 ) x + 20 cos ( 2 x ) + 15}{4}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{10 cos ( 2 ) x + 20 cos ( 2 x ) + 15}{4} = \frac{10 cos ( 2 ) x}{4} + \frac{20 cos ( 2 x )}{4} + \frac{15}{4}

= \frac{10 cos ( 2 ) x}{4} + \frac{20 cos ( 2 x )}{4} + \frac{15}{4}

Cancel

\frac{10 cos ( 2 ) x}{4} : \frac{5 cos ( 2 ) x}{2}

= \frac{5 cos ( 2 ) x}{2} + \frac{20 cos ( 2 x )}{4} + \frac{15}{4}

Divide the numbers:

\frac{20}{4} = 5

= \frac{5 cos ( 2 ) x}{2} + 5 cos (2 x) + \frac{15}{4}

\frac{( x + 3 ) ^{2}}{( x - 5 )}

(1 - i + t)^{2}

(2 + 5) (1 + 2)

(x^{2} + 4) (x^{2} - 12 x + 4)

(x^{2} + 22 \cdot x + 4) \cdot (x^{2} - 22 \cdot x + 4)

What is expand (5(2cos(2)x+4cos(2x)+3))/4 ?
The solution to expand (5(2cos(2)x+4cos(2x)+3))/4 is (5cos(2)x)/2+5cos(2x)+15/4