What is expand ((4x+1)^2)/((x+3)(x-2)) ?

The solution to expand ((4x+1)^2)/((x+3)(x-2)) is (16x^2+8x+1)/(x^2+x-6)

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expand ((4x+1)^2)/((x+3)(x-2))

expand

\frac{( 4 x + 1 ) ^{2}}{( x + 3 ) ( x - 2 )}

\frac{16 x ^{2} + 8 x + 1}{x ^{2} + x - 6}

Solution steps

\frac{( 4 x + 1 ) ^{2}}{( x + 3 ) ( x - 2 )}

(4 x + 1)^{2} = 16 x^{2} + 8 x + 1

= \frac{16 x ^{2} + 8 x + 1}{( x + 3 ) ( x - 2 )}

Expand

(x + 3) (x - 2) : x^{2} + x - 6

= \frac{16 x ^{2} + 8 x + 1}{x ^{2} + x - 6}

\frac{( 3 n + 4 ) ^{2}}{9}

- \frac{2 ( 9 - 2 3 )}{3}

\frac{1}{4} (8 x + 16)

\frac{2}{x + 3} - \frac{6}{x - 3}

cos^{2} (x) (1 - x) (7 - x^{3})

What is expand ((4x+1)^2)/((x+3)(x-2)) ?
The solution to expand ((4x+1)^2)/((x+3)(x-2)) is (16x^2+8x+1)/(x^2+x-6)