What is expand (x^{1/3}-1)^2 ?

The solution to expand (x^{1/3}-1)^2 is x^{2/3}-2x^{1/3}+1

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expand (x^{1/3}-1)^2

expand

(x^{\frac{1}{3}} - 1)^{2}

x^{\frac{2}{3}} - 2 x^{\frac{1}{3}} + 1

Solution steps

(x^{\frac{1}{3}} - 1)^{2}

Apply Perfect Square Formula:

(a - b)^{2} = a^{2} - 2 ab + b^{2}

(x^{\frac{1}{3}} - 1)^{2} = (x^{\frac{1}{3}})^{2} - 2 x^{\frac{1}{3}} \cdot 1 + 1^{2}

= (x^{\frac{1}{3}})^{2} - 2 x^{\frac{1}{3}} \cdot 1 + 1^{2}

(x^{\frac{1}{3}})^{2} = x^{\frac{2}{3}}

2 x^{\frac{1}{3}} \cdot 1 = 2 x^{\frac{1}{3}}

1^{2} = 1

= x^{\frac{2}{3}} - 2 x^{\frac{1}{3}} + 1

\frac{1}{2 j ( 4 + j ^{4} π )}

\frac{d}{d x} ((Q (x, y)) (x^{2} + y (x, d)^{2}) d y (x, d))

(e^{\frac{jπ}{2}} - e^{- \frac{jπ}{2}})^{3}

\frac{( 2 x - 1 ) ( 3 - x )}{( x - 1 ) ( x + 3 )}

(0.2 s + 10) \frac{d}{d s} (0.2 s + 10)

What is expand (x^{1/3}-1)^2 ?
The solution to expand (x^{1/3}-1)^2 is x^{2/3}-2x^{1/3}+1