What is expand (pe^{bx}+ne^{-bx})cos(ax) ?

The solution to expand (pe^{bx}+ne^{-bx})cos(ax) is e^{bx}pcos(xa)+ne^{-bx}cos(xa)

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expand (pe^{bx}+ne^{-bx})cos(ax)

expand

(p e^{b x} + n e^{- b x}) cos (a x)

e^{b x} p cos (x a) + n e^{- b x} cos (x a)

Solution steps

(p e^{b x} + n e^{- b x}) cos (a x)

= cos (x a) (e^{b x} p + n e^{- b x})

Apply the distributive law:

a (b + c) = ab + a c

a = cos (a x), b = p e^{b x}, c = n e^{- b x}

= cos (a x) p e^{b x} + cos (a x) n e^{- b x}

= e^{b x} p cos (x a) + n e^{- b x} cos (x a)

\frac{1}{120 ( x - 1 ) ( x - 2 ) ( x - 3 ) ( x - 4 )}

(5 - x + 17) \cdot (5 + x + 17)

(x + 2 - 4)^{2}

(\frac{4 x}{5} - \frac{1}{2}) (\frac{4 x}{5} + \frac{1}{2})

\frac{( - W x ^{2} - P x + W Lx + P L ) ( L - x )}{4}

What is expand (pe^{bx}+ne^{-bx})cos(ax) ?
The solution to expand (pe^{bx}+ne^{-bx})cos(ax) is e^{bx}pcos(xa)+ne^{-bx}cos(xa)