What is expand ,A(2, 3/4)yB(3/5 ,-1/2)y ?

The solution to expand ,A(2, 3/4)yB(3/5 ,-1/2)y is +, 3/5 (2*3/4 ,)AyyB,-, 1/2 (2*3/4 ,)AyyB

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expand ,A(2, 3/4)yB(3/5 ,-1/2)y

expand

, A (2, \frac{3}{4}) y B (\frac{3}{5}, - \frac{1}{2}) y

+, \frac{3}{5} (2 \cdot \frac{3}{4},) A yy B, -, \frac{1}{2} (2 \cdot \frac{3}{4},) A yy B

Solution steps

, A (2, \frac{3}{4}) y B (\frac{3}{5}, - \frac{1}{2}) y

=, (2 \cdot \frac{3}{4},) (\frac{3}{5}, - \frac{1}{2}) A yy B

Apply the distributive law:

a (b - c) = ab - a c

a = +, A (2, \frac{3}{4}) y B y, b = \frac{3}{5},, c = \frac{1}{2}

= +, A (2, \frac{3}{4}) y B y \frac{3}{5}, -, A (2, \frac{3}{4}) y B y \frac{1}{2}

= +, \frac{3}{5} (2 \cdot \frac{3}{4},) A yy B, -, \frac{1}{2} (2 \cdot \frac{3}{4},) A yy B

\frac{x - 3}{( x - 1 ) ( x + 3 )}

\frac{54 e ^{x} ( - e ^{x} + 2 )}{( 3 e ^{x} + 6 ) ^{3}}

\frac{2 ( 1 - 13 )}{3}

- e^{- x} x^{3} - 3 (e^{- x} x^{2} - 2 (- e^{- x} x - e^{- x}))

What is expand ,A(2, 3/4)yB(3/5 ,-1/2)y ?
The solution to expand ,A(2, 3/4)yB(3/5 ,-1/2)y is +, 3/5 (2*3/4 ,)AyyB,-, 1/2 (2*3/4 ,)AyyB