What is expand (derivative of t^2+9)/((3t-6)^9) ?

The solution to expand (derivative of t^2+9)/((3t-6)^9) is

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expand (derivative of t^2+9)/((3t-6)^9)

expand

\frac{\frac{d}{d x} ( t ^{2} + 9 )}{( 3 t - 6 ) ^{9}}

\frac{\frac{d}{d x} ( t ^{2} + 9 )}{19683 t ^{9} - 354294 t ^{8} + 2834352 t ^{7} - 13226976 t ^{6} + 39680928 t ^{5} - 79361856 t ^{4} + 105815808 t ^{3} - 90699264 t ^{2} + 45349632 t - 10077696}

Solution steps

\frac{\frac{d}{d x} ( t ^{2} + 9 )}{( 3 t - 6 ) ^{9}}

(3 t - 6)^{9} = 19683 t^{9} - 354294 t^{8} + 2834352 t^{7} - 13226976 t^{6} + 39680928 t^{5} - 79361856 t^{4} + 105815808 t^{3} - 90699264 t^{2} + 45349632 t - 10077696

= \frac{\frac{d}{d x} ( t ^{2} + 9 )}{19683 t ^{9} - 354294 t ^{8} + 2834352 t ^{7} - 13226976 t ^{6} + 39680928 t ^{5} - 79361856 t ^{4} + 105815808 t ^{3} - 90699264 t ^{2} + 45349632 t - 10077696}

(2 x - \frac{1}{2} y)^{3}

\frac{( 1 + x ) ^{n} - 1}{x}

\frac{- 0.17 ( a + h ) ^{3} + 2.21 ( a + h ) - 2.04}{h}

\frac{x ^{2} + x - x y - y}{p ( 3 p + 2 q - 5 )}

(sin (y)) (x + sin (y)) d x

What is expand (derivative of t^2+9)/((3t-6)^9) ?
The solution to expand (derivative of t^2+9)/((3t-6)^9) is