What is 2(2^{1/2}-4) ?

The solution to 2(2^{1/2}-4) is 2*2^{1/2}-8

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simplify 2(2^{1/2}-4)

simplify

2 (2^{\frac{1}{2}} - 4)

2 \cdot 2^{\frac{1}{2}} - 8

Decimal Notation

- 5.17157 \dots

Solution steps

2 (2^{\frac{1}{2}} - 4)

Apply the distributive law:

a (b - c) = ab - a c

2 (2^{\frac{1}{2}} - 4) = 2 \cdot 2^{\frac{1}{2}} - 2 \cdot 4

= 2 \cdot 2^{\frac{1}{2}} - 2 \cdot 4

Multiply the numbers:

2 \cdot 4 = 8

= 2 \cdot 2^{\frac{1}{2}} - 8

3 (7 + 10)

\frac{4 s ( 8 + 4 s + s ^{2} )}{( 2 + s ) ^{2} ( 4 + s )}

- \frac{5 ( x - 140 ) ( x - 180 ) ( x - 240 )}{64}

3 (1 + 2 sin (θ))

- 2 x + 1 (x - 8)