What are the solutions to the equation 3t^2+4t+8=-6t ?

The solutions to the equation 3t^2+4t+8=-6t are t=-4/3 ,t=-2

Find the zeros of 3t^2+4t+8=-6t

The zeros of 3t^2+4t+8=-6t are t=-4/3 ,t=-2

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3 t^{2} + 4 t + 8 = - 6 t

t = - \frac{4}{3}, t = - 2

Solution steps

3 t^{2} + 4 t + 8 = - 6 t

Move

6 t

to the left side

3 t^{2} + 10 t + 8 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 3 \cdot 8}{2 \cdot 3}

1 0^{2} - 4 \cdot 3 \cdot 8 = 2

t_{1, 2} = \frac{- 10 \pm 2}{2 \cdot 3}

Separate the solutions

t_{1} = \frac{- 10 + 2}{2 \cdot 3}, t_{2} = \frac{- 10 - 2}{2 \cdot 3}

t = \frac{- 10 + 2}{2 \cdot 3} : - \frac{4}{3}

t = \frac{- 10 - 2}{2 \cdot 3} : - 2

The solutions to the quadratic equation are:

t = - \frac{4}{3}, t = - 2

- 42 \geq 40 + 41 c

\frac{1}{e ^{- 2}}

\frac{5 a ^{7}}{10 a ^{3}}

6 g^{3} - 24 g^{2} + 24 g

81 u^{2} - 4

What are the solutions to the equation 3t^2+4t+8=-6t ?
The solutions to the equation 3t^2+4t+8=-6t are t=-4/3 ,t=-2
Find the zeros of 3t^2+4t+8=-6t
The zeros of 3t^2+4t+8=-6t are t=-4/3 ,t=-2