What is expand (e^{3x+1})(2x+1)^3 ?

The solution to expand (e^{3x+1})(2x+1)^3 is 8e^{3x+1}x^3+12e^{3x+1}x^2+6e^{3x+1}x+e^{3x+1}

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expand (e^{3x+1})(2x+1)^3

expand

(e^{3 x + 1}) (2 x + 1)^{3}

8 e^{3 x + 1} x^{3} + 12 e^{3 x + 1} x^{2} + 6 e^{3 x + 1} x + e^{3 x + 1}

Solution steps

(e^{3 x + 1}) (2 x + 1)^{3}

Remove parentheses:

(a) = a

= e^{3 x + 1} (2 x + 1)^{3}

(2 x + 1)^{3} = 8 x^{3} + 12 x^{2} + 6 x + 1

= e^{3 x + 1} (8 x^{3} + 12 x^{2} + 6 x + 1)

Distribute parentheses

= e^{3 x + 1} \cdot 8 x^{3} + e^{3 x + 1} \cdot 12 x^{2} + e^{3 x + 1} \cdot 6 x + e^{3 x + 1} \cdot 1

= 8 e^{3 x + 1} x^{3} + 12 e^{3 x + 1} x^{2} + 6 e^{3 x + 1} x + 1 \cdot e^{3 x + 1}

Multiply:

1 \cdot e^{3 x + 1} = e^{3 x + 1}

= 8 e^{3 x + 1} x^{3} + 12 e^{3 x + 1} x^{2} + 6 e^{3 x + 1} x + e^{3 x + 1}

(1, 2, 1, 1) y (2, 1, - 1, 3)

- \frac{5}{7} (x + 8)

(e^{5} x \cdot 5 sin (2 x) + cos (2 x) \cdot 2 e^{5} x) (- 4 sin (8 x))

\frac{s ( s + 1 )}{( s + 2 ) ( s + 3 ) ( s + 4 )}

\frac{19 x + 181}{( x + 10 ) ( x + 9 )}

What is expand (e^{3x+1})(2x+1)^3 ?
The solution to expand (e^{3x+1})(2x+1)^3 is 8e^{3x+1}x^3+12e^{3x+1}x^2+6e^{3x+1}x+e^{3x+1}