What is expand (2x)/((x^2-4)^2) ?

The solution to expand (2x)/((x^2-4)^2) is (2x)/(x^4-8x^2+16)

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expand (2x)/((x^2-4)^2)

expand

\frac{2 x}{( x ^{2} - 4 ) ^{2}}

\frac{2 x}{x ^{4} - 8 x ^{2} + 16}

Solution steps

\frac{2 x}{( x ^{2} - 4 ) ^{2}}

(x^{2} - 4)^{2} = x^{4} - 8 x^{2} + 16

= \frac{2 x}{x ^{4} - 8 x ^{2} + 16}

(a - λ) (b - λ) (c - λ) (d - λ) (e - λ)

(sin (θ) - 2 r cos^{2} (θ)) d r + r cos (θ) (2 r sin (θ) + 1) d θ

\frac{z ^{2} - 6 z + 8}{( z + 1 ) ( z + 2 )}

8 \cdot 6

y^{\frac{1}{3}} (y^{\frac{1}{3}} - y^{\frac{3}{2}})

What is expand (2x)/((x^2-4)^2) ?
The solution to expand (2x)/((x^2-4)^2) is (2x)/(x^4-8x^2+16)