What is expand 4cos(θ)(8tan(θ)+5sec(θ)) ?

The solution to expand 4cos(θ)(8tan(θ)+5sec(θ)) is 32sin(θ)+20

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expand 4cos(θ)(8tan(θ)+5sec(θ))

expand

4 cos (θ) (8 tan (θ) + 5 sec (θ))

32 sin (θ) + 20

Solution steps

4 cos (θ) (8 tan (θ) + 5 sec (θ))

Apply the distributive law:

a (b + c) = ab + a c

4 cos (θ) (8 tan (θ) + 5 sec (θ)) = 4 cos (θ) \cdot 8 tan (θ) + 4 cos (θ) \cdot 5 sec (θ)

= 4 cos (θ) \cdot 8 tan (θ) + 4 cos (θ) \cdot 5 sec (θ)

Simplify

4 cos (θ) \cdot 8 tan (θ) + 4 cos (θ) \cdot 5 sec (θ) : 32 sin (θ) + 20

= 32 sin (θ) + 20

\frac{d ^{2}}{d x ^{2}} ((y) (x sin (x) - cos (x)))

\frac{15 s ^{2} - 68 s + 133}{( s - 1 ) ( s ^{2} - 6 s + 25 )}

\frac{( - s ^{3} - A \cdot s ^{2} - 3 s - 4 A )}{( ( s ^{2} + 4 ) ( s ^{2} + 9 ) )}

(3 x^{2} + 2 x y + 4 y^{2}) d x

0.00646 (\frac{12.5}{s} + 1)

What is expand 4cos(θ)(8tan(θ)+5sec(θ)) ?
The solution to expand 4cos(θ)(8tan(θ)+5sec(θ)) is 32sin(θ)+20