What is expand-1/((x+1)^2(x+6)) ?

The solution to expand-1/((x+1)^2(x+6)) is -1/(x^3+8x^2+13x+6)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand-1/((x+1)^2(x+6))

expand

- \frac{1}{( x + 1 ) ^{2} ( x + 6 )}

- \frac{1}{x ^{3} + 8 x ^{2} + 13 x + 6}

Solution steps

- \frac{1}{( x + 1 ) ^{2} ( x + 6 )}

(x + 1)^{2} = x^{2} + 2 x + 1

= - \frac{1}{( x ^{2} + 2 x + 1 ) ( x + 6 )}

Expand

(x^{2} + 2 x + 1) (x + 6) : x^{3} + 8 x^{2} + 13 x + 6

= - \frac{1}{x ^{3} + 8 x ^{2} + 13 x + 6}

cos (\frac{π}{4} - θ)

e^{3 (t - 6)} U (t - 6)

y (3 - \frac{1}{2} x - \frac{3}{2} y)^{2}

(8)^{2}

(1 - e^{- 2 x}) (1 - e^{- 2 y})

What is expand-1/((x+1)^2(x+6)) ?
The solution to expand-1/((x+1)^2(x+6)) is -1/(x^3+8x^2+13x+6)