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Popular >

expand (x+3)(x+3)'

Solution

expand

(x + 3) (x + 3)^{'}

Solution

x (x + 3)' + 3 (x + 3)'

Solution steps

(x + 3) (x + 3)^{'}

Apply the distributive law:

a (b + c) = ab + a c

a = (x + 3)^{'}, b = x, c = 3

= (x + 3)^{^{'}} x + (x + 3)^{^{'}} 3

= x (x + 3)^{^{'}} + 3 (x + 3)^{^{'}}

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Frequently Asked Questions (FAQ)

What is expand (x+3)(x+3)' ?
The solution to expand (x+3)(x+3)' is x(x+3)'+3(x+3)'