What is expand ((-3x^2+3x)^2)/2 ?

The solution to expand ((-3x^2+3x)^2)/2 is (9x^4)/2-9x^3+(9x^2)/2

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expand ((-3x^2+3x)^2)/2

expand

\frac{( - 3 x ^{2} + 3 x ) ^{2}}{2}

\frac{9 x ^{4}}{2} - 9 x^{3} + \frac{9 x ^{2}}{2}

Solution steps

\frac{( - 3 x ^{2} + 3 x ) ^{2}}{2}

(- 3 x^{2} + 3 x)^{2} = 9 x^{4} - 18 x^{3} + 9 x^{2}

= \frac{9 x ^{4} - 18 x ^{3} + 9 x ^{2}}{2}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{9 x ^{4} - 18 x ^{3} + 9 x ^{2}}{2} = \frac{9 x ^{4}}{2} - \frac{18 x ^{3}}{2} + \frac{9 x ^{2}}{2}

= \frac{9 x ^{4}}{2} - \frac{18 x ^{3}}{2} + \frac{9 x ^{2}}{2}

Divide the numbers:

\frac{18}{2} = 9

= \frac{9 x ^{4}}{2} - 9 x^{3} + \frac{9 x ^{2}}{2}

(3 x - 5 y^{2} - 3 x + 19 + 5)^{2}

sin ((n + \frac{1}{2}) π)

(3 t - 3) e^{\frac{t + 2}{3}}

(x - 3 + 7) (x - 3 - 7)

\frac{π ^{2}}{4} + (- 1, - 1 + π) (x, y + \frac{π}{2})

What is expand ((-3x^2+3x)^2)/2 ?
The solution to expand ((-3x^2+3x)^2)/2 is (9x^4)/2-9x^3+(9x^2)/2