What is expand (x+1)\times ln^2(x+1) ?

The solution to expand (x+1)\times ln^2(x+1) is xln^2(x+1)+ln^2(x+1)

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expand (x+1)\times ln^2(x+1)

expand

(x + 1) \cdot ln^{2} (x + 1)

x ln^{2} (x + 1) + ln^{2} (x + 1)

Solution steps

(x + 1) ln^{2} (x + 1)

= ln^{2} (x + 1) (x + 1)

Apply the distributive law:

a (b + c) = ab + a c

a = ln^{2} (x + 1), b = x, c = 1

= ln^{2} (x + 1) x + ln^{2} (x + 1) \cdot 1

= x ln^{2} (x + 1) + 1 \cdot ln^{2} (x + 1)

Multiply:

1 \cdot ln^{2} (x + 1) = ln^{2} (x + 1)

= x ln^{2} (x + 1) + ln^{2} (x + 1)

sec (2 (arcsec (\frac{25}{7}) + 2 πn))

\frac{( x + 1 ) ( x - 1 )}{x + 2}

3 (1 + \frac{1}{x ^{2}})

e^{x - 5} (x - 1)^{2}

2 (x + \frac{1}{4})

What is expand (x+1)\times ln^2(x+1) ?
The solution to expand (x+1)\times ln^2(x+1) is xln^2(x+1)+ln^2(x+1)