What is (k^2+1)(1.1)+((k-k^2-1)/3)(3) ?

The solution to (k^2+1)(1.1)+((k-k^2-1)/3)(3) is 0.1k^2+k+0.1

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simplify (k^2+1)(1.1)+((k-k^2-1)/3)(3)

simplify

(k^{2} + 1) (1.1) + (\frac{k - k ^{2} - 1}{3}) (3)

0.1 k^{2} + k + 0.1

Solution steps

(k^{2} + 1) (1.1) + (\frac{k - k ^{2} - 1}{3}) (3)

Simplify

(k^{2} + 1) (1.1) + (\frac{k - k ^{2} - 1}{3}) (3) : (k^{2} + 1) \cdot 1.1 + \frac{k - k ^{2} - 1}{3} \cdot 3

= (k^{2} + 1) \cdot 1.1 + \frac{k - k ^{2} - 1}{3} \cdot 3

Cross-cancel common factor:

3

= (k^{2} + 1) \cdot 1.1 + k - k^{2} - 1

= 1.1 (k^{2} + 1) + k - k^{2} - 1

Expand

1.1 (k^{2} + 1) : 1.1 k^{2} + 1.1

= 1.1 k^{2} + 1.1 + k - k^{2} - 1

Group like terms

= 1.1 k^{2} - k^{2} + k + 1.1 - 1

Add similar elements:

1.1 k^{2} - k^{2} = 0.1 k^{2}

= 0.1 k^{2} + k + 1.1 - 1

Subtract the numbers:

1.1 - 1 = 0.1

= 0.1 k^{2} + k + 0.1

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What is (k^2+1)(1.1)+((k-k^2-1)/3)(3) ?
The solution to (k^2+1)(1.1)+((k-k^2-1)/3)(3) is 0.1k^2+k+0.1