What is t(x)x^{''}+(2t(x)-2)x^'+2x ?

The solution to t(x)x^{''}+(2t(x)-2)x^'+2x is tx^{1+'^2}+x^'(2tx-2)+2x

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simplify t(x)x^{''}+(2t(x)-2)x^'+2x

simplify

t (x) x^{^{''}} + (2 t (x) - 2) x^{^{'}} + 2 x

t x^{1 +'^{2}} + x^{'} (2 t x - 2) + 2 x

Solution steps

t (x) x^{^{''}} + (2 t (x) - 2) x^{^{'}} + 2 x

Remove parentheses:

(a) = a

= t x x^{^{^{''}}} + (2 t x - 2) x^{^{^{'}}} + 2 x

\frac{10 ( x + 4 ) ( x + 6 )}{x ( x + 1 ) ( x + 7 ) ( x + 8 ) ( x + 9 )}

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3 (4 x^{3} cos (x) - x^{4} sin (x))

2 (\frac{2}{2} x + \frac{2}{2} y)^{2}

What is t(x)x^{''}+(2t(x)-2)x^'+2x ?
The solution to t(x)x^{''}+(2t(x)-2)x^'+2x is tx^{1+'^2}+x^'(2tx-2)+2x