What is expand ((a^2+2a+4)(a^2-2a+4))/a ?

The solution to expand ((a^2+2a+4)(a^2-2a+4))/a is a^3+4a+(16)/a

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expand ((a^2+2a+4)(a^2-2a+4))/a

expand

\frac{( a ^{2} + 2 a + 4 ) ( a ^{2} - 2 a + 4 )}{a}

a^{3} + 4 a + \frac{16}{a}

Solution steps

\frac{( a ^{2} + 2 a + 4 ) ( a ^{2} - 2 a + 4 )}{a}

Expand

(a^{2} + 2 a + 4) (a^{2} - 2 a + 4) : a^{4} + 4 a^{2} + 16

= \frac{a ^{4} + 4 a ^{2} + 16}{a}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{a ^{4} + 4 a ^{2} + 16}{a} = \frac{a ^{4}}{a} + \frac{4 a ^{2}}{a} + \frac{16}{a}

= \frac{a ^{4}}{a} + \frac{4 a ^{2}}{a} + \frac{16}{a}

Cancel

\frac{a ^{4}}{a} : a^{3}

= a^{3} + \frac{4 a ^{2}}{a} + \frac{16}{a}

Cancel

\frac{4 a ^{2}}{a} : 4 a

= a^{3} + 4 a + \frac{16}{a}

x (2 - ln (x))

\frac{d}{d t} ((x) (4 x + 2 y))

(e + 3) (e - 3)

(2 x - 3)^{3}

(d x + e) \cdot (x^{2} - x + 1) \cdot (x - 1)

What is expand ((a^2+2a+4)(a^2-2a+4))/a ?
The solution to expand ((a^2+2a+4)(a^2-2a+4))/a is a^3+4a+(16)/a