What is expand ((2x-3)(x+1))/((x-4)(x+3)) ?

The solution to expand ((2x-3)(x+1))/((x-4)(x+3)) is (2x^2-x-3)/(x^2-x-12)

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expand ((2x-3)(x+1))/((x-4)(x+3))

expand

\frac{( 2 x - 3 ) ( x + 1 )}{( x - 4 ) ( x + 3 )}

\frac{2 x ^{2} - x - 3}{x ^{2} - x - 12}

Solution steps

\frac{( 2 x - 3 ) ( x + 1 )}{( x - 4 ) ( x + 3 )}

Expand

(x - 4) (x + 3) : x^{2} - x - 12

= \frac{( 2 x - 3 ) ( x + 1 )}{x ^{2} - x - 12}

Expand

(2 x - 3) (x + 1) : 2 x^{2} - x - 3

= \frac{2 x ^{2} - x - 3}{x ^{2} - x - 12}

\frac{x ^{2} ( x + 2 )}{2 ( 2 x + 9 ) ( x + 8 )}

f oco (0, - 3)

(x - 3) (x + 2)

(- 2 x^{2} + x^{3} - 4 + x) l e f t (2 x + 1)

(x - 3) (x + 5)

What is expand ((2x-3)(x+1))/((x-4)(x+3)) ?
The solution to expand ((2x-3)(x+1))/((x-4)(x+3)) is (2x^2-x-3)/(x^2-x-12)