What is expand (4x-5)/((x^2-2x+2)^{3/2)} ?

The solution to expand (4x-5)/((x^2-2x+2)^{3/2)} is (4x)/((x^2-2x+2)^{3/2)}-5/((x^2-2x+2)^{3/2)}

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expand (4x-5)/((x^2-2x+2)^{3/2)}

expand

\frac{4 x - 5}{( x ^{2} - 2 x + 2 ) ^{\frac{3}{2}}}

\frac{4 x}{( x ^{2} - 2 x + 2 ) ^{\frac{3}{2}}} - \frac{5}{( x ^{2} - 2 x + 2 ) ^{\frac{3}{2}}}

Solution steps

\frac{4 x - 5}{( x ^{2} - 2 x + 2 ) ^{\frac{3}{2}}}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{4 x - 5}{( x ^{2} - 2 x + 2 ) ^{\frac{3}{2}}} = \frac{4 x}{( x ^{2} - 2 x + 2 ) ^{\frac{3}{2}}} - \frac{5}{( x ^{2} - 2 x + 2 ) ^{\frac{3}{2}}}

= \frac{4 x}{( x ^{2} - 2 x + 2 ) ^{\frac{3}{2}}} - \frac{5}{( x ^{2} - 2 x + 2 ) ^{\frac{3}{2}}}

\frac{3 s ^{2} + 2}{3 ( s ^{3} - s ^{2} + 4 s - 4 )}

(1 + \frac{2}{x}) (3 - \frac{1}{x})

\frac{x + 1}{x ( x + 2 )}

4000 (- \frac{x}{4} + 3) e^{- \frac{x}{4} - 1}

lo g_{10} (9) (9 x)

What is expand (4x-5)/((x^2-2x+2)^{3/2)} ?
The solution to expand (4x-5)/((x^2-2x+2)^{3/2)} is (4x)/((x^2-2x+2)^{3/2)}-5/((x^2-2x+2)^{3/2)}