What is expand 4/((4x-3)(4n+1)) ?

The solution to expand 4/((4x-3)(4n+1)) is 4/(16nx+4x-12n-3)

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expand 4/((4x-3)(4n+1))

expand

\frac{4}{( 4 x - 3 ) ( 4 n + 1 )}

\frac{4}{16 n x + 4 x - 12 n - 3}

Solution steps

\frac{4}{( 4 x - 3 ) ( 4 n + 1 )}

Expand

(4 x - 3) (4 n + 1) : 16 n x + 4 x - 12 n - 3

= \frac{4}{16 n x + 4 x - 12 n - 3}

\frac{z ( z - 3 )}{z ^{2} - 6 z + 8}

\frac{( 1 + 2 x ) ^{\frac{1}{2}}}{( 1 + x ) ^{3}}

\frac{( - 12.921 x ^{2} - 25.842 x + 4380 )}{( x + 1 ) ^{2}} - 20

(6 - x + 4)^{2}

\frac{( x + 3 ) ^{2}}{4}

What is expand 4/((4x-3)(4n+1)) ?
The solution to expand 4/((4x-3)(4n+1)) is 4/(16nx+4x-12n-3)