What is expand (t-1)^2sin(3t) ?

The solution to expand (t-1)^2sin(3t) is t^2sin(3t)-2tsin(3t)+sin(3t)

Popular >

expand (t-1)^2sin(3t)

expand

(t - 1)^{2} sin (3 t)

t^{2} sin (3 t) - 2 t sin (3 t) + sin (3 t)

Solution steps

(t - 1)^{2} sin (3 t)

= sin (3 t) (t - 1)^{2}

Expand

(t - 1)^{2} : t^{2} - 2 t + 1

= sin (3 t) (t^{2} - 2 t + 1)

Apply the distributive law:

m (a + b + c) = ma + mb + m c

sin (3 t) (t^{2} - 2 t + 1) = sin (3 t) t^{2} + sin (3 t) (- 2 t) + sin (3 t) \cdot 1

= sin (3 t) t^{2} + sin (3 t) (- 2 t) + sin (3 t) \cdot 1

Simplify

sin (3 t) t^{2} + sin (3 t) (- 2 t) + sin (3 t) \cdot 1 : t^{2} sin (3 t) - 2 t sin (3 t) + sin (3 t)

= t^{2} sin (3 t) - 2 t sin (3 t) + sin (3 t)

\frac{1}{( s + 2 ) ( s + 4 )}

\frac{3 ( 8 x ^{3} - 5 )}{( 2 x ^{4} - 5 x ) ^{4}}

((cos^{2} (t))) \cdot (- sin (t) + cos (t))

(arctan (x - 2) - 5 x^{\frac{3}{2}})^{2}

δ (x - 4) - e^{- 4 x} cos (2 x) + 3 x^{4}

What is expand (t-1)^2sin(3t) ?
The solution to expand (t-1)^2sin(3t) is t^2sin(3t)-2tsin(3t)+sin(3t)