What is expand (x^4-2)(x^2+4)' ?

The solution to expand (x^4-2)(x^2+4)' is x^4(x^2+4)'-2(x^2+4)'

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expand (x^4-2)(x^2+4)'

expand

(x^{4} - 2) (x^{2} + 4)^{'}

x^{4} (x^{2} + 4)' - 2 (x^{2} + 4)'

Solution steps

(x^{4} - 2) (x^{2} + 4)^{'}

Apply the distributive law:

a (b - c) = ab - a c

a = (x^{2} + 4)^{'}, b = x^{4}, c = 2

= (x^{2} + 4)^{^{'}} x^{4} - (x^{2} + 4)^{^{'}} 2

= x^{4} (x^{2} + 4)^{^{'}} - 2 (x^{2} + 4)^{^{'}}

- e x^{x} (ln (x) + 1) + e^{x}

\frac{800 ( 20 3 - 1 )}{9}

\frac{s ^{2} + 4 s - 5}{( s ^{2} + 4 s + 13 ) ^{2}}

8 (\frac{π}{6} + \frac{3}{4})

\frac{s ^{2} + 12}{( s ^{2} + 9 ) ( s - 1 ) ( s + 1 ) ( s + 2 )}

What is expand (x^4-2)(x^2+4)' ?
The solution to expand (x^4-2)(x^2+4)' is x^4(x^2+4)'-2(x^2+4)'