What is expand (2x+2Δx+(-4))(3x+7) ?

The solution to expand (2x+2Δx+(-4))(3x+7) is 6Δx^2+6x^2+14Δx+2x-28

Popular >

expand (2x+2Δx+(-4))(3x+7)

expand

(2 x + 2Δ x + (- 4)) (3 x + 7)

6Δ x^{2} + 6 x^{2} + 14Δ x + 2 x - 28

Solution steps

(2 x + 2Δ x + (- 4)) (3 x + 7)

Distribute parentheses

= 2 x \cdot 3 x + 2 x \cdot 7 + 2Δ x \cdot 3 x + 2Δ x \cdot 7 + (- 4) \cdot 3 x + (- 4) \cdot 7

= 2 \cdot 3 xx + 2 \cdot 7 x + 2 \cdot 3Δ xx + 2 \cdot 7Δ x + (- 4) \cdot 3 x + (- 4) \cdot 7

Simplify

2 \cdot 3 xx + 2 \cdot 7 x + 2 \cdot 3Δ xx + 2 \cdot 7Δ x + (- 4) \cdot 3 x + (- 4) \cdot 7 : 6Δ x^{2} + 6 x^{2} + 14Δ x + 2 x - 28

= 6Δ x^{2} + 6 x^{2} + 14Δ x + 2 x - 28

(0.5 + i)^{4}

(x + x)^{3}

d g (- sin (\frac{π}{12}) - (0.12) cos (\frac{π}{12}))

(n^{2} - n)^{2}

\frac{8 e ^{- π s}}{( s ^{2} + 1 ) ( s ^{2} + 9 )}

What is expand (2x+2Δx+(-4))(3x+7) ?
The solution to expand (2x+2Δx+(-4))(3x+7) is 6Δx^2+6x^2+14Δx+2x-28