What is expand (1-e^x)(1+e^x) ?

The solution to expand (1-e^x)(1+e^x) is 1-e^{2x}

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expand (1-e^x)(1+e^x)

expand

(1 - e^{x}) (1 + e^{x})

1 - e^{2 x}

Solution steps

(1 - e^{x}) (1 + e^{x})

Apply Difference of Two Squares Formula:

(a - b) (a + b) = a^{2} - b^{2}

a = 1, b = e^{x}

= 1^{2} - (e^{x})^{2}

Simplify

1^{2} - (e^{x})^{2} : 1 - e^{2 x}

= 1 - e^{2 x}

[ln^{2} (1 + x) \cdot (1 + x)]^{^{'}}

\frac{( e ^{- s} + s )}{s ( s - 5 ) ( s - 6 )}

(1 - e^{i \cdot θ})^{2}

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(n^{2} + n - 1 - kn) (n^{2} + n - 1 + kn)

What is expand (1-e^x)(1+e^x) ?
The solution to expand (1-e^x)(1+e^x) is 1-e^{2x}