What is expand (2x-1)/((x-3)(x+2)) ?

The solution to expand (2x-1)/((x-3)(x+2)) is (2x-1)/(x^2-x-6)

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expand (2x-1)/((x-3)(x+2))

expand

\frac{2 x - 1}{( x - 3 ) ( x + 2 )}

\frac{2 x - 1}{x ^{2} - x - 6}

Solution steps

\frac{2 x - 1}{( x - 3 ) ( x + 2 )}

Expand

(x - 3) (x + 2) : x^{2} - x - 6

= \frac{2 x - 1}{x ^{2} - x - 6}

2^{3}

(a + b - ab) (c + d - c d) (e + f - e f)

2^{8}

4 π (- r^{2} + 4)

\frac{\partial}{\partial x} ((z) (z^{4} + z^{2} x^{2} - 6))

What is expand (2x-1)/((x-3)(x+2)) ?
The solution to expand (2x-1)/((x-3)(x+2)) is (2x-1)/(x^2-x-6)