What is tan^2(a)*(2cos^2(a)+sin^2(a)-1) ?

The solution to tan^2(a)*(2cos^2(a)+sin^2(a)-1) is sin^2(a)

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simplify tan^2(a)*(2cos^2(a)+sin^2(a)-1)

simplify

tan^{2} (a) \cdot (2 cos^{2} (a) + sin^{2} (a) - 1)

sin^{2} (a)

Solution steps

tan^{2} (a) (2 cos^{2} (a) + sin^{2} (a) - 1)

Use the Pythagorean identity:

1 = cos^{2} (x) + sin^{2} (x)

1 - sin^{2} (x) = cos^{2} (x)

= tan^{2} (a) (2 cos^{2} (a) - cos^{2} (a))

cos^{2} (a) tan^{2} (a) = sin^{2} (a)

= sin^{2} (a)

Factor

2 cos^{2} (a) - cos^{2} (a) : cos^{2} (a)

= sin^{2} (a)

30 + 42

ln^{4} (x - 3) (x^{3} + 1)^{5} (2 cos (x) - 3)

P (- 4, 7) y Q (- 10, - 2)

\frac{s ^{2} - 8 s + 16}{( s - 5 ) ( s ^{2} - 4 s + 1 )}

\frac{4 ( 16 - 3 6 )}{15}

What is tan^2(a)*(2cos^2(a)+sin^2(a)-1) ?
The solution to tan^2(a)*(2cos^2(a)+sin^2(a)-1) is sin^2(a)