What is expand (2(x^3-2))/((x-3)(x^2+3x+9)) ?

The solution to expand (2(x^3-2))/((x-3)(x^2+3x+9)) is (2x^3-4)/(x^3-27)

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expand (2(x^3-2))/((x-3)(x^2+3x+9))

expand

\frac{2 ( x ^{3} - 2 )}{( x - 3 ) ( x ^{2} + 3 x + 9 )}

\frac{2 x ^{3} - 4}{x ^{3} - 27}

Solution steps

\frac{2 ( x ^{3} - 2 )}{( x - 3 ) ( x ^{2} + 3 x + 9 )}

Expand

(x - 3) (x^{2} + 3 x + 9) : x^{3} - 27

= \frac{2 ( x ^{3} - 2 )}{x ^{3} - 27}

Expand

2 (x^{3} - 2) : 2 x^{3} - 4

= \frac{2 x ^{3} - 4}{x ^{3} - 27}

(3 - sin (x))^{2}

\frac{- 1 - 1 - 4 ( - π - 4 πn )}{2}

(2 t - e^{4 t})^{2}

(8 x + 7) (- e^{- x})

(- 1 + t)^{2} + (- 4 - 2 t)^{2} + (5 + 2 t)^{2}

What is expand (2(x^3-2))/((x-3)(x^2+3x+9)) ?
The solution to expand (2(x^3-2))/((x-3)(x^2+3x+9)) is (2x^3-4)/(x^3-27)