What is expand P(2,8)yC(0,-2) ?

The solution to expand P(2,8)yC(0,-2) is 0*(2*8,)CPy,-2(2*8,)CPy

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand P(2,8)yC(0,-2)

expand

P (2, 8) y C (0, - 2)

0 \cdot (2 \cdot 8,) CP y, - 2 (2 \cdot 8,) CP y

Solution steps

P (2, 8) y C (0, - 2)

= (2 \cdot 8,) (0, - 2) CP y

Apply the distributive law:

a (b - c) = ab - a c

a = P (2, 8) y C, b = 0,, c = 2

= P (2, 8) y C \cdot 0, - P (2, 8) y C \cdot 2

= 0 \cdot (2 \cdot 8,) CP y, - 2 (2 \cdot 8,) CP y

2 (\frac{11}{5} e^{- 2 t} + \frac{4}{5} e^{3 t})

(e^{4 x} + 5)^{2}

(a - b) x^{2} + (a + b) x + c + (e - i) x^{2} + (e + i) x + o

3 sin (7 (x + 3)) + 4

A (4, 2) B (6, - 3)

What is expand P(2,8)yC(0,-2) ?
The solution to expand P(2,8)yC(0,-2) is 0*(2*8,)CPy,-2(2*8,)CPy