What is expand 5x^{2/3}(8x-4x^{1/4}) ?

The solution to expand 5x^{2/3}(8x-4x^{1/4}) is 40x^{5/3}-20x^{11/12}

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expand 5x^{2/3}(8x-4x^{1/4})

expand

5 x^{\frac{2}{3}} (8 x - 4 x^{\frac{1}{4}})

40 x^{\frac{5}{3}} - 20 x^{\frac{11}{12}}

Solution steps

5 x^{\frac{2}{3}} (8 x - 4 x^{\frac{1}{4}})

Apply the distributive law:

a (b - c) = ab - a c

5 x^{\frac{2}{3}} (8 x - 4 x^{\frac{1}{4}}) = 5 x^{\frac{2}{3}} \cdot 8 x - 5 x^{\frac{2}{3}} \cdot 4 x^{\frac{1}{4}}

= 5 x^{\frac{2}{3}} \cdot 8 x - 5 x^{\frac{2}{3}} \cdot 4 x^{\frac{1}{4}}

5 x^{\frac{2}{3}} \cdot 8 x = 40 x^{\frac{5}{3}}

5 x^{\frac{2}{3}} \cdot 4 x^{\frac{1}{4}} = 20 x^{\frac{11}{12}}

= 40 x^{\frac{5}{3}} - 20 x^{\frac{11}{12}}

sec^{2} (5 x) + 3 (x - 1)^{2} - \frac{2}{3 x}

(3 (t + 1), - 6 (t - 1)) \cdot (- 4 (t + 1), 2 (t - 1))

(5 x - 3)^{2}

lo g_{6} (4)

\frac{3 x ^{2}}{( x - 3 ) ^{2}}

What is expand 5x^{2/3}(8x-4x^{1/4}) ?
The solution to expand 5x^{2/3}(8x-4x^{1/4}) is 40x^{5/3}-20x^{11/12}