What is expand 2(2x^2+3x-10)^2 ?

The solution to expand 2(2x^2+3x-10)^2 is 8x^4+24x^3-62x^2-120x+200

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expand 2(2x^2+3x-10)^2

expand

2 (2 x^{2} + 3 x - 10)^{2}

8 x^{4} + 24 x^{3} - 62 x^{2} - 120 x + 200

Solution steps

2 (2 x^{2} + 3 x - 10)^{2}

(2 x^{2} + 3 x - 10)^{2} = 4 x^{4} + 12 x^{3} - 31 x^{2} - 60 x + 100

= 2 (4 x^{4} + 12 x^{3} - 31 x^{2} - 60 x + 100)

Distribute parentheses

= 2 \cdot 4 x^{4} + 2 \cdot 12 x^{3} + 2 (- 31 x^{2}) + 2 (- 60 x) + 2 \cdot 100

Apply minus-plus rules

+ (- a) = - a

= 2 \cdot 4 x^{4} + 2 \cdot 12 x^{3} - 2 \cdot 31 x^{2} - 2 \cdot 60 x + 2 \cdot 100

Simplify

2 \cdot 4 x^{4} + 2 \cdot 12 x^{3} - 2 \cdot 31 x^{2} - 2 \cdot 60 x + 2 \cdot 100 : 8 x^{4} + 24 x^{3} - 62 x^{2} - 120 x + 200

= 8 x^{4} + 24 x^{3} - 62 x^{2} - 120 x + 200

- \frac{2 x y}{( x ^{2} + 1 ) ( e ^{y} + ln ( x ^{2} + 1 ) )}

\frac{1}{4} (\frac{2 - x}{3})^{3}

(x - 2 a x + a)^{2}

(\frac{x}{3} - \frac{2 y}{5}) (\frac{x}{3} + \frac{2 y}{5})

\frac{x ^{2} - x - 1}{( x + 5 ) ( x ^{2} + 4 )}

What is expand 2(2x^2+3x-10)^2 ?
The solution to expand 2(2x^2+3x-10)^2 is 8x^4+24x^3-62x^2-120x+200