What is expand (5x^2+6x+9)/((x-3)^2*(x+1)^2) ?

The solution to expand (5x^2+6x+9)/((x-3)^2*(x+1)^2) is (5x^2+6x+9)/(x^4-4x^3-2x^2+12x+9)

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expand (5x^2+6x+9)/((x-3)^2*(x+1)^2)

expand

\frac{5 x ^{2} + 6 x + 9}{( x - 3 ) ^{2} \cdot ( x + 1 ) ^{2}}

\frac{5 x ^{2} + 6 x + 9}{x ^{4} - 4 x ^{3} - 2 x ^{2} + 12 x + 9}

Solution steps

\frac{5 x ^{2} + 6 x + 9}{( x - 3 ) ^{2} ( x + 1 ) ^{2}}

(x - 3)^{2} = x^{2} - 6 x + 9

= \frac{5 x ^{2} + 6 x + 9}{( x ^{2} - 6 x + 9 ) ( x + 1 ) ^{2}}

(x + 1)^{2} = x^{2} + 2 x + 1

= \frac{5 x ^{2} + 6 x + 9}{( x ^{2} - 6 x + 9 ) ( x ^{2} + 2 x + 1 )}

Expand

(x^{2} - 6 x + 9) (x^{2} + 2 x + 1) : x^{4} - 4 x^{3} - 2 x^{2} + 12 x + 9

= \frac{5 x ^{2} + 6 x + 9}{x ^{4} - 4 x ^{3} - 2 x ^{2} + 12 x + 9}

\frac{2 n}{( 1 - x ) ^{2}}

(tan (z) - sin (x) sin (y)) d x + cos (x) cos (y) d y

\frac{( x ^{2} + 15 )}{( x + 5 ) ^{2} ( x ^{2} + 5 )}

(2 + 2 i)^{7}

- \frac{3 x ( x - 8 )}{8}

What is expand (5x^2+6x+9)/((x-3)^2*(x+1)^2) ?
The solution to expand (5x^2+6x+9)/((x-3)^2*(x+1)^2) is (5x^2+6x+9)/(x^4-4x^3-2x^2+12x+9)