What is expand cos(θ)(2sin(θ)+1) ?

The solution to expand cos(θ)(2sin(θ)+1) is cos(θ)+sin(2θ)

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expand cos(θ)(2sin(θ)+1)

expand

cos (θ) (2 sin (θ) + 1)

cos (θ) + sin (2 θ)

Solution steps

cos (θ) (2 sin (θ) + 1)

Apply the distributive law:

a (b + c) = ab + a c

cos (θ) (2 sin (θ) + 1) = cos (θ) \cdot 2 sin (θ) + cos (θ) \cdot 1

= cos (θ) \cdot 2 sin (θ) + cos (θ) \cdot 1

Simplify

cos (θ) \cdot 2 sin (θ) + cos (θ) \cdot 1 : cos (θ) + sin (2 θ)

= cos (θ) + sin (2 θ)

\frac{5}{( s ^{2} + 25 ) ( 1 + 10 e ^{10 t} )}

- 2 \cdot (\frac{y}{3} + \frac{x}{6})

(1 - t) (0.3) + t (4.6)

\frac{2 d x}{( x ^{2} - 1 ) ^{2}}

\frac{( a - b ) ^{2}}{a + b}

What is expand cos(θ)(2sin(θ)+1) ?
The solution to expand cos(θ)(2sin(θ)+1) is cos(θ)+sin(2θ)