What is expand (x^2-5x-9)/((2x+3)(x-4)) ?

The solution to expand (x^2-5x-9)/((2x+3)(x-4)) is (x^2-5x-9)/(2x^2-5x-12)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (x^2-5x-9)/((2x+3)(x-4))

expand

\frac{x ^{2} - 5 x - 9}{( 2 x + 3 ) ( x - 4 )}

\frac{x ^{2} - 5 x - 9}{2 x ^{2} - 5 x - 12}

Solution steps

\frac{x ^{2} - 5 x - 9}{( 2 x + 3 ) ( x - 4 )}

Expand

(2 x + 3) (x - 4) : 2 x^{2} - 5 x - 12

= \frac{x ^{2} - 5 x - 9}{2 x ^{2} - 5 x - 12}

(sec (θ) + tan (θ)) (sin (θ) - 1)

8 x - 9 (4 - x = 23)

(2 i + 1)^{4}

(a_{0} x + a_{1} y)^{2} + p y

(1 - y)^{2}

What is expand (x^2-5x-9)/((2x+3)(x-4)) ?
The solution to expand (x^2-5x-9)/((2x+3)(x-4)) is (x^2-5x-9)/(2x^2-5x-12)