What is expand (2x(x+1)(x-1))/(x^4+6x^2+1) ?

The solution to expand (2x(x+1)(x-1))/(x^4+6x^2+1) is (2x^3-2x)/(x^4+6x^2+1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (2x(x+1)(x-1))/(x^4+6x^2+1)

expand

\frac{2 x ( x + 1 ) ( x - 1 )}{x ^{4} + 6 x ^{2} + 1}

\frac{2 x ^{3} - 2 x}{x ^{4} + 6 x ^{2} + 1}

Solution steps

\frac{2 x ( x + 1 ) ( x - 1 )}{x ^{4} + 6 x ^{2} + 1}

Expand

2 x (x + 1) (x - 1) : 2 x^{3} - 2 x

= \frac{2 x ^{3} - 2 x}{x ^{4} + 6 x ^{2} + 1}

\frac{7}{( x - 1 ) ( x + 2 )}

(\frac{5}{x - 10} + 8 (100 - x)) (x - 10)

5 y^{3} d x - y^{2} (- 2 x + y^{2} x^{4}) d y

(3 + 3 cos (x))^{2}

e^{t} (1 + e^{2})

What is expand (2x(x+1)(x-1))/(x^4+6x^2+1) ?
The solution to expand (2x(x+1)(x-1))/(x^4+6x^2+1) is (2x^3-2x)/(x^4+6x^2+1)