What is expand 6(-2/3)^4+2(-2/3)^3-12(-2/3)^2+3 ?

The solution to expand 6(-2/3)^4+2(-2/3)^3-12(-2/3)^2+3 is -47/27

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expand 6(-2/3)^4+2(-2/3)^3-12(-2/3)^2+3

expand

6 (- \frac{2}{3})^{4} + 2 (- \frac{2}{3})^{3} - 12 (- \frac{2}{3})^{2} + 3

- \frac{47}{27}

Decimal Notation

- 1.74074 \dots

Solution steps

6 (- \frac{2}{3})^{4} + 2 (- \frac{2}{3})^{3} - 12 (- \frac{2}{3})^{2} + 3

6 (- \frac{2}{3})^{4} = \frac{32}{27}

2 (- \frac{2}{3})^{3} = - \frac{16}{27}

= \frac{32}{27} - \frac{16}{27} - 12 (- \frac{2}{3})^{2} + 3

Combine the fractions

\frac{32}{27} - \frac{16}{27} : \frac{16}{27}

= \frac{16}{27} - 12 (- \frac{2}{3})^{2} + 3

12 (- \frac{2}{3})^{2} = \frac{16}{3}

= \frac{16}{27} - \frac{16}{3} + 3

Convert element to fraction:

3 = \frac{3}{1}

= \frac{3}{1} + \frac{16}{27} - \frac{16}{3}

Least Common Multiplier of

1, 27, 3 : 27

Adjust Fractions based on the LCM

= \frac{81}{27} + \frac{16}{27} - \frac{144}{27}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{81 + 16 - 144}{27}

Add/Subtract the numbers:

81 + 16 - 144 = - 47

= \frac{- 47}{27}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{47}{27}

a (2, - 1, 0) + b (5, 5, - 2) + c (0, 1, 1)

8 x^{2} + 4 x - 2 \cdot (\frac{x ^{5}}{5} + \frac{x ^{3}}{3})

(n + 3)!

1 - \frac{1}{2}

\frac{- e ^{- x} x + e ^{- x}}{( x - 2 ) ^{2}}

What is expand 6(-2/3)^4+2(-2/3)^3-12(-2/3)^2+3 ?
The solution to expand 6(-2/3)^4+2(-2/3)^3-12(-2/3)^2+3 is -47/27