What is expand-1/((s+2)(s+1)(s-1)) ?

The solution to expand-1/((s+2)(s+1)(s-1)) is -1/(s^3-s+2s^2-2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand-1/((s+2)(s+1)(s-1))

expand

- \frac{1}{( s + 2 ) ( s + 1 ) ( s - 1 )}

- \frac{1}{s ^{3} - s + 2 s ^{2} - 2}

Solution steps

- \frac{1}{( s + 2 ) ( s + 1 ) ( s - 1 )}

Expand

(s + 2) (s + 1) (s - 1) : s^{3} - s + 2 s^{2} - 2

= - \frac{1}{s ^{3} + 2 s ^{2} - s - 2}

\frac{\frac{d}{d x} ( x - 5 )}{( x + 2 ) ^{2}}

1 - cos (x) (1 - cos (x))

\frac{1}{2}

\frac{5 ( 651 10 - 64 1054 )}{248}

- \frac{v ( e ^{- k t} - 1 )}{k}

What is expand-1/((s+2)(s+1)(s-1)) ?
The solution to expand-1/((s+2)(s+1)(s-1)) is -1/(s^3-s+2s^2-2)