What are the solutions to the equation 81x^2+144x+64=0 ?

The solutions to the equation 81x^2+144x+64=0 are x=-8/9

Find the zeros of 81x^2+144x+64=0

The zeros of 81x^2+144x+64=0 are x=-8/9

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81 x^{2} + 144 x + 64 = 0

x = - \frac{8}{9}

Solution steps

81 x^{2} + 144 x + 64 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 144 \pm 14 4 ^{2} - 4 \cdot 81 \cdot 64}{2 \cdot 81}

14 4^{2} - 4 \cdot 81 \cdot 64 = 0

x_{1, 2} = \frac{- 144 \pm 0}{2 \cdot 81}

x = \frac{- 144}{2 \cdot 81}

\frac{- 144}{2 \cdot 81} = - \frac{8}{9}

x = - \frac{8}{9}

The solution to the quadratic equation is:

x = - \frac{8}{9}

\frac{40}{- 8}

2 x - 7 = 13

\frac{3 + 5 i}{1 - 2 i}

(x + 4)^{2} = 49

6 x^{2} - 13 x + 6

What are the solutions to the equation 81x^2+144x+64=0 ?
The solutions to the equation 81x^2+144x+64=0 are x=-8/9
Find the zeros of 81x^2+144x+64=0
The zeros of 81x^2+144x+64=0 are x=-8/9