What is expand 1/24 x(x+2)(x+1)(x-1) ?

The solution to expand 1/24 x(x+2)(x+1)(x-1) is (x^4)/(24)-(x^2)/(24)+(x^3)/(12)-x/(12)

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expand 1/24 x(x+2)(x+1)(x-1)

expand

\frac{1}{24} x (x + 2) (x + 1) (x - 1)

\frac{x ^{4}}{24} - \frac{x ^{2}}{24} + \frac{x ^{3}}{12} - \frac{x}{12}

Solution steps

\frac{1}{24} x (x + 2) (x + 1) (x - 1)

Expand

\frac{1}{24} x (x + 2) (x + 1) (x - 1) : \frac{1}{24} x (x + 2) (x^{2} - 1)

= \frac{1}{24} x (x + 2) (x^{2} - 1)

Apply FOIL method

(x + 2) (x^{2} - 1) : x^{3} - x + 2 x^{2} - 2

= \frac{1}{24} x (x^{3} - x + 2 x^{2} - 2)

Distribute parentheses

= \frac{1}{24} x x^{3} + \frac{1}{24} x (- x) + \frac{1}{24} x \cdot 2 x^{2} + \frac{1}{24} x (- 2)

Simplify

\frac{1}{24} x x^{3} + \frac{1}{24} x (- x) + \frac{1}{24} x \cdot 2 x^{2} + \frac{1}{24} x (- 2) : \frac{x ^{4}}{24} - \frac{x ^{2}}{24} + \frac{x ^{3}}{12} - \frac{x}{12}

= \frac{x ^{4}}{24} - \frac{x ^{2}}{24} + \frac{x ^{3}}{12} - \frac{x}{12}

\frac{( 4 x ^{2} + 1 + x )}{( x ^{2} ) ( x ^{2} - 2 s + 5 )}

(9 + x^{2}) 9 + x^{2}

\frac{( ( 1 - x ) ^{3} )}{3}

(e^{18 x} + e^{- 18 x})^{2}

5 + i (- 3 + 26)

What is expand 1/24 x(x+2)(x+1)(x-1) ?
The solution to expand 1/24 x(x+2)(x+1)(x-1) is (x^4)/(24)-(x^2)/(24)+(x^3)/(12)-x/(12)