What is expand 3(x-1=2-(x+5)) ?

The solution to expand 3(x-1=2-(x+5)) is 3x-3=-3x-13

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expand 3(x-1=2-(x+5))

expand

3 (x - 1 = 2 - (x + 5))

3 x - 3 = - 3 x - 13

Solution steps

3 (x - 1 = 2 - (x + 5))

= 3 (x - 1 \cdot 2 = - (x + 5))

Distribute parentheses

= 3 x + 3 (- 1 = 2) + 3 (- (x + 5))

Apply minus-plus rules

+ (- a) = - a

3 x - 3 \cdot 1 = 2 - 3 (x + 5)

Simplify

3 x - 3 \cdot 1 = 2 - 3 (x + 5) : 3 x - 3 = - 3 x - 13

3 x - 3 = - 3 x - 13

\frac{1}{3} (1 - x + \frac{xx}{2})^{3}

\frac{5 ( 3 - 13 )}{4}

\frac{( e ^{- 7 s} )}{( s - 1 ) ( s - 3 )}

(x + e^{\frac{x}{2}} y)^{2}

\frac{1}{( cos ( θ ) + i sin ( θ ) ) ^{2}}

What is expand 3(x-1=2-(x+5)) ?
The solution to expand 3(x-1=2-(x+5)) is 3x-3=-3x-13