What is expand-((8x)/y-w/t)^2 ?

The solution to expand-((8x)/y-w/t)^2 is -(64x^2t^2-16xwyt+w^2y^2)/(y^2t^2)

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expand-((8x)/y-w/t)^2

expand

- (\frac{8 x}{y} - \frac{w}{t})^{2}

- \frac{64 x ^{2} t ^{2} - 16 x w y t + w ^{2} y ^{2}}{y ^{2} t ^{2}}

Solution steps

- (\frac{8 x}{y} - \frac{w}{t})^{2}

Apply Perfect Square Formula:

(a - b)^{2} = a^{2} - 2 ab + b^{2}

(\frac{8 x}{y} - \frac{w}{t})^{2} = (\frac{8 x}{y})^{2} - 2 \cdot \frac{8 x}{y} \cdot \frac{w}{t} + (\frac{w}{t})^{2}

= - ((\frac{8 x}{y})^{2} - 2 \cdot \frac{8 x}{y} \cdot \frac{w}{t} + (\frac{w}{t})^{2})

Simplify

(\frac{8 x}{y})^{2} - 2 \cdot \frac{8 x}{y} \cdot \frac{w}{t} + (\frac{w}{t})^{2} : \frac{64 x ^{2} t ^{2} - 16 x w y t + w ^{2} y ^{2}}{y ^{2} t ^{2}}

= - \frac{64 x ^{2} t ^{2} - 16 x w y t + w ^{2} y ^{2}}{y ^{2} t ^{2}}

(12 x^{(3)} + 6 x^{(2)} - 2 x + 3) d x

(2 a - (x - c)^{2} + y^{2})^{2}

\frac{( 1 - sin ( x ) + t ^{2} ) t}{( 1 + t ^{2} ) ^{2}}

(2 cos (x) - 1) (2 cos (x) + 1)

What is expand-((8x)/y-w/t)^2 ?
The solution to expand-((8x)/y-w/t)^2 is -(64x^2t^2-16xwyt+w^2y^2)/(y^2t^2)