What is (1/x-x)(y-1/y) ?

The solution to (1/x-x)(y-1/y) is ((-x^2+1)(y^2-1))/(yx)

Popular >

simplify (1/x-x)(y-1/y)

simplify

(\frac{1}{x} - x) (y - \frac{1}{y})

\frac{( - x ^{2} + 1 ) ( y ^{2} - 1 )}{y x}

Solution steps

(\frac{1}{x} - x) (y - \frac{1}{y})

Join

\frac{1}{x} - x : \frac{- x ^{2} + 1}{x}

= \frac{- x ^{2} + 1}{x} (y - \frac{1}{y})

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( - x ^{2} + 1 ) ( y - \frac{1}{y} )}{x}

Simplify

(- x^{2} + 1) (y - \frac{1}{y}) : \frac{( - x ^{2} + 1 ) ( y ^{2} - 1 )}{y}

= \frac{\frac{( - x ^{2} + 1 ) ( y ^{2} - 1 )}{y}}{x}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{( - x ^{2} + 1 ) ( y ^{2} - 1 )}{y x}

(6 x^{2} - 7 y^{2}) d x - 14 x y d y

\frac{1}{2} (- \frac{1}{7} cos (7 x) + cos (x)) + C

(- p - 50 \cdot p)^{2}

A (2, - 3) B (5, - 1)

\frac{( 5 x )}{( ( x - 1 ) ( x ^{(2)} + 2 x + 5 ) )}

What is (1/x-x)(y-1/y) ?
The solution to (1/x-x)(y-1/y) is ((-x^2+1)(y^2-1))/(yx)