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Popular >

d/(d{x)}(({z})(2{x}{y}{z}-e^{{z}}))

Solution

\frac{d}{d x} ((z) (2 x y z - e^{z}))

Solution

2 y z^{2}

Solution steps

\frac{d}{d x} ((z) (2 x y z - e^{z}))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= z \frac{d}{d x} (2 x y z - e^{z})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= z (\frac{d}{d x} (2 x y z) - \frac{d}{d x} (e^{z}))

\frac{d}{d x} (2 x y z) = 2 y z

\frac{d}{d x} (e^{z}) = 0

= z (2 y z - 0)

Simplify

z (2 y z - 0) : 2 y z^{2}

= 2 y z^{2}

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Frequently Asked Questions (FAQ)

What is the d/(d{x)}(({z})(2{x}{y}{z}-e^{{z}})) ?
The d/(d{x)}(({z})(2{x}{y}{z}-e^{{z}})) is 2{y}{z}^2
What is the first d/(d{x)}(({z})(2{x}{y}{z}-e^{{z}})) ?
The first d/(d{x)}(({z})(2{x}{y}{z}-e^{{z}})) is 2{y}{z}^2