What is 2197/2000 (2+log_{3}(2)) ?

The solution to 2197/2000 (2+log_{3}(2)) is 2197/1000+2197/2000 log_{3}(2)

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simplify 2197/2000 (2+log_{3}(2))

simplify

\frac{2197}{2000} (2 + lo g_{3} (2))

\frac{2197}{1000} + \frac{2197}{2000} lo g_{3} (2)

Solution steps

\frac{2197}{2000} (2 + lo g_{3} (2))

Apply the distributive law:

a (b + c) = ab + a c

\frac{2197}{2000} (2 + lo g_{3} (2)) = \frac{2197}{2000} \cdot 2 + \frac{2197}{2000} lo g_{3} (2)

= \frac{2197}{2000} \cdot 2 + \frac{2197}{2000} lo g_{3} (2)

\frac{2197}{2000} \cdot 2 = \frac{2197}{1000}

= \frac{2197}{1000} + \frac{2197}{2000} lo g_{3} (2)

(2 + i 3)^{4}

(x^{3} + 3) (3 - x^{3})

- \frac{s e ^{- \frac{a}{5}}}{10 ( s ^{2} + 1 ) ( s + 4 ) ( s + 5 )}

\frac{( 1 - i ) ^{13}}{64}

\frac{1}{s ( a s + 1 ) ( b s + 1 )}

What is 2197/2000 (2+log_{3}(2)) ?
The solution to 2197/2000 (2+log_{3}(2)) is 2197/1000+2197/2000 log_{3}(2)