What is (x-3)(x+i)(x+2i) ?

The solution to (x-3)(x+i)(x+2i) is (x-3)(x^2-2)+(x-3)*3xi

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simplify (x-3)(x+i)(x+2i)

simplify

(x - 3) (x + i) (x + 2 i)

(x - 3) (x^{2} - 2) + (x - 3) \cdot 3 x i

Solution steps

(x - 3) (x + i) (x + 2 i)

Apply complex arithmetic rule:

(a + bi) (c + d i) = (a c - b d) + (a d + b c) i

= (x - 3) ((xx - 1 \cdot 2) + (x \cdot 2 + 1 \cdot x) i)

Simplify

(xx - 1 \cdot 2) + (x \cdot 2 + 1 \cdot x) i : (x^{2} - 2) + 3 x i

= (x - 3) ((x^{2} - 2) + 3 x i)

Distribute parentheses

= (x - 3) (x^{2} - 2) + (x - 3) \cdot 3 x i

\frac{( x ^{2} + 1 )}{( x ( x ^{2} + 2 ) )}

(x cos (β) + l y cos (θ))^{2} + (x sin (β) - l sin (θ))^{2}

\frac{5 x ^{2} - 6 x + 7}{( x + 1 ) ( x ^{2} + 1 )}

\frac{- 2 s ^{2} + 7 s - 2}{( s - 1 ) ^{2} ( s - 2 ) ( s ^{2} + 4 )}

(x - 5) (x - 6 i)

What is (x-3)(x+i)(x+2i) ?
The solution to (x-3)(x+i)(x+2i) is (x-3)(x^2-2)+(x-3)*3xi