What is expand ((1-u)^3)/3 ?

The solution to expand ((1-u)^3)/3 is -(u^3)/3+u^2-u+1/3

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expand ((1-u)^3)/3

expand

\frac{( 1 - u ) ^{3}}{3}

- \frac{u ^{3}}{3} + u^{2} - u + \frac{1}{3}

Solution steps

\frac{( 1 - u ) ^{3}}{3}

(1 - u)^{3} = 1 - 3 u + 3 u^{2} - u^{3}

= \frac{1 - 3 u + 3 u ^{2} - u ^{3}}{3}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{1 - 3 u + 3 u ^{2} - u ^{3}}{3} = \frac{1}{3} - \frac{3 u}{3} + \frac{3 u ^{2}}{3} - \frac{u ^{3}}{3}

= \frac{1}{3} - \frac{3 u}{3} + \frac{3 u ^{2}}{3} - \frac{u ^{3}}{3}

Divide the numbers:

\frac{3}{3} = 1

= \frac{1}{3} - u + u^{2} - \frac{u ^{3}}{3}

Rewrite in standard form

= - \frac{u ^{3}}{3} + u^{2} - u + \frac{1}{3}

x (\frac{( 7 - x ) ^{2}}{18} - \frac{1}{2})

\frac{1}{2} + \frac{3}{44} ((5 \cdot 1.2) - \frac{( 1. 2 ^{3} )}{3})

(2 hm + 4 d am) am

(e^{t} sin (t) - e^{t} cos (t))^{2}

\frac{2 n + 1}{2 ( n + 1 )}

What is expand ((1-u)^3)/3 ?
The solution to expand ((1-u)^3)/3 is -(u^3)/3+u^2-u+1/3