What is expand 1/((s-1)(s^2+1)) ?

The solution to expand 1/((s-1)(s^2+1)) is 1/(s^3+s-s^2-1)

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expand 1/((s-1)(s^2+1))

expand

\frac{1}{( s - 1 ) ( s ^{2} + 1 )}

\frac{1}{s ^{3} + s - s ^{2} - 1}

Solution steps

\frac{1}{( s - 1 ) ( s ^{2} + 1 )}

Expand

(s - 1) (s^{2} + 1) : s^{3} + s - s^{2} - 1

= \frac{1}{s ^{3} + s - s ^{2} - 1}

\frac{1}{125} (25 t + 13) sin (5 t) + (t + \frac{1}{25}) cos (5 t)

(y - x^{2} + y^{2}) d x - x d y

\frac{2 s + 8}{( s + 1 ) ( s + 2 )}

(tan (2 x)) (1 - tan^{2} (x))

A (- 3, 6) y B (3, - 2)

What is expand 1/((s-1)(s^2+1)) ?
The solution to expand 1/((s-1)(s^2+1)) is 1/(s^3+s-s^2-1)