What is expand (2/65 e^{-8x}(9sin(x)-7cos(x))+c)e^{8x} ?

The solution to expand (2/65 e^{-8x}(9sin(x)-7cos(x))+c)e^{8x} is 18/65 sin(x)-14/65 cos(x)+ce^{8x}

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expand (2/65 e^{-8x}(9sin(x)-7cos(x))+c)e^{8x}

expand

(\frac{2}{65} e^{- 8 x} (9 sin (x) - 7 cos (x)) + c) e^{8 x}

\frac{18}{65} sin (x) - \frac{14}{65} cos (x) + c e^{8 x}

Solution steps

(\frac{2}{65} e^{- 8 x} (9 sin (x) - 7 cos (x)) + c) e^{8 x}

= e^{8 x} (\frac{2}{65} e^{- 8 x} (9 sin (x) - 7 cos (x)) + c)

Apply the distributive law:

a (b + c) = ab + a c

a = e^{8 x}, b = \frac{2}{65} e^{- 8 x} (9 sin (x) - 7 cos (x)), c = c

= e^{8 x} \frac{2}{65} e^{- 8 x} (9 sin (x) - 7 cos (x)) + e^{8 x} c

= \frac{2}{65} e^{8 x} e^{- 8 x} (9 sin (x) - 7 cos (x)) + c e^{8 x}

Simplify

\frac{2}{65} e^{8 x} e^{- 8 x} (9 sin (x) - 7 cos (x)) + c e^{8 x} : \frac{18}{65} sin (x) - \frac{14}{65} cos (x) + c e^{8 x}

= \frac{18}{65} sin (x) - \frac{14}{65} cos (x) + c e^{8 x}

(x^{\frac{9}{5}} - 4 x^{\frac{4}{5}})^{2}

(\frac{80 - p}{2}) \cdot (p - (w + 4))

(x + 3) + i (y - 3)

(\frac{5}{6} + \frac{1}{6})^{4}

What is expand (2/65 e^{-8x}(9sin(x)-7cos(x))+c)e^{8x} ?
The solution to expand (2/65 e^{-8x}(9sin(x)-7cos(x))+c)e^{8x} is 18/65 sin(x)-14/65 cos(x)+ce^{8x}