What is expand-6(3e^{3x}cos(2x)-2e^{3x}sin(2x)) ?

The solution to expand-6(3e^{3x}cos(2x)-2e^{3x}sin(2x)) is -18e^{3x}cos(2x)+12e^{3x}sin(2x)

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expand-6(3e^{3x}cos(2x)-2e^{3x}sin(2x))

expand

- 6 (3 e^{3 x} cos (2 x) - 2 e^{3 x} sin (2 x))

- 18 e^{3 x} cos (2 x) + 12 e^{3 x} sin (2 x)

Solution steps

- 6 (3 e^{3 x} cos (2 x) - 2 e^{3 x} sin (2 x))

Apply the distributive law:

a (b - c) = ab - a c

a = - 6, b = 3 e^{3 x} cos (2 x), c = 2 e^{3 x} sin (2 x)

= - 6 \cdot 3 e^{3 x} cos (2 x) - (- 6) \cdot 2 e^{3 x} sin (2 x)

Apply minus-plus rules

- (- a) = a

= - 6 \cdot 3 e^{3 x} cos (2 x) + 6 \cdot 2 e^{3 x} sin (2 x)

Simplify

- 6 \cdot 3 e^{3 x} cos (2 x) + 6 \cdot 2 e^{3 x} sin (2 x) : - 18 e^{3 x} cos (2 x) + 12 e^{3 x} sin (2 x)

= - 18 e^{3 x} cos (2 x) + 12 e^{3 x} sin (2 x)

(21) (2 x + y, x)

l im x \Rightarrow 1 (x^{2} - x) sin (x - 1)

(2 - 1 - x)^{6}

(16 - x^{2}) e^{x^{2}}

x^{3} (a_{0} + \frac{7}{4}) - 4 a_{0} x - 1

What is expand-6(3e^{3x}cos(2x)-2e^{3x}sin(2x)) ?
The solution to expand-6(3e^{3x}cos(2x)-2e^{3x}sin(2x)) is -18e^{3x}cos(2x)+12e^{3x}sin(2x)