What is the d/(dθ)(({x}(θ))(3(1-cos(θ)))) ?

The d/(dθ)(({x}(θ))(3(1-cos(θ)))) is 3(d/(dθ)({x}(θ))(1-cos(θ))+sin(θ){x}(θ))

What is the first d/(dθ)(({x}(θ))(3(1-cos(θ)))) ?

The first d/(dθ)(({x}(θ))(3(1-cos(θ)))) is 3(d/(dθ)({x}(θ))(1-cos(θ))+sin(θ){x}(θ))

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\frac{d}{d θ} ((x (θ)) (3 (1 - cos (θ))))

3 (\frac{d}{d θ} (x (θ)) (1 - cos (θ)) + sin (θ) x (θ))

Solution steps

\frac{d}{d θ} ((x (θ)) (3 (1 - cos (θ))))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d θ} (x (θ) (1 - cos (θ)))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x (θ), g = 1 - cos (θ)

= 3 (\frac{d}{d θ} (x (θ)) (1 - cos (θ)) + \frac{d}{d θ} (1 - cos (θ)) x (θ))

\frac{d}{d θ} (1 - cos (θ)) = sin (θ)

= 3 (\frac{d}{d θ} (x (θ)) (1 - cos (θ)) + sin (θ) x (θ))

- \frac{- 5 x + 4}{2 ln ( 5 ) x ( - x + 1 )}

(x - 4) (x + 7) (x - 2) (x + 2)

(1 - \frac{1}{x}) (1 + \frac{1}{z ^{2}}) (1 + \frac{1}{z})

\frac{4 s + 2 s ^{2} + 8}{( s ^{2} + 4 ) ( s + 1 ) ^{2}}

\frac{6}{( s ^{'} + 7 s + 10 ) ( s ^{2} + 4 )}

What is the d/(dθ)(({x}(θ))(3(1-cos(θ)))) ?
The d/(dθ)(({x}(θ))(3(1-cos(θ)))) is 3(d/(dθ)({x}(θ))(1-cos(θ))+sin(θ){x}(θ))
What is the first d/(dθ)(({x}(θ))(3(1-cos(θ)))) ?
The first d/(dθ)(({x}(θ))(3(1-cos(θ)))) is 3(d/(dθ)({x}(θ))(1-cos(θ))+sin(θ){x}(θ))